Express excited and ground state in DressdState§
From
{∣n,+⟩=sinθ∣0⟩+eiϕcosθ∣1⟩∣n,−⟩=cosθ∣0⟩−eiϕsinθ∣1⟩
We get
{∣0⟩=sinθ∣n,+⟩+cosθ∣n,−⟩∣1⟩=e−iϕ(cosθ∣n,+⟩−sinθ∣n,−⟩)
Time evolution of DressedState§
En,±=ℏ(ωn+2Δ±21Ω)
Thus
∣ψ(t)⟩=e−iωnte−i2Δt(c−e2iΩt∣n,−⟩+c+e−2iΩt∣n,+⟩)
But for what we are trying to do next, let's use the ∣0⟩,∣1⟩ basis.
∣ψ(t)⟩=e−iωnte−i2Δt(c−e2iΩt(cosθ∣0⟩−eiϕsinθ∣1⟩)+c+e−2iΩt(sinθ∣0⟩+eiϕcosθ∣1⟩))=e−iωnte−i2Δt((c+e−2iΩtsinθ+c−e2iΩtcosθ)∣0⟩+(c+e−2iΩteiϕcosθ−c−e2iΩteiϕsinθ)∣1⟩)
Probabilities of§
Being on excited state§
With δ=arg(c+c−∗)
⟨1∣ϕ⟩2=c+2cos2θ+c−2sin2θ−2∣c+∣∣c−∣cosθsinθcos(Ωt−δ)
Which we want to link back to Rabi frequency and Detuning, thus we need 2θ everywhere, and note c+2+c−2=1 as a normalization condition
⟨1∣ϕ⟩2=2c+2(1+cos2θ)+2c−2(1−cos2θ)−∣c+∣∣c−∣sin2θcos(Ωt−δ)=2c+2+c−2+cos2θ(2c+2−c−2)−∣c+∣∣c−∣sin2θcos(Ωt−δ)=21+cos2θ(2c+2−c−2)−∣c+∣∣c−∣sin2θcos(Ωt−δ)
Thus
Pe(t)=21−ΩΔ(2c+2−c−2)−∣c+∣∣c−∣ΩΩRcos(Ωt−δ)
Being on Ground state§
Easily, as the algebra is extremely similar,
Pg(t)=21−ΩΔ(2c+2−c−2)+∣c+∣∣c−∣ΩΩRcos(Ωt−δ)
Which also can be seen as
Pg(t)=1−Pe(t)
Rabi Frequency§
Notational Note§
When Δ=0 we obtain ΩR=Ω, thus one is called Rabi frequency one is the Rabi frequency on resonant since Δ=0 means on resonant.
Physical significant§
As seen in the formula, it is the frequency that drive the state between excited and ground state, which we can carry out the calculation also for ground state and other states as well and the Rabi frequency will give showing up.
Rabi Splitting§
The fact that purely due to an existing field that didn't need to be controled, as it can also be from vacuum fluctuation, will cause the coupled system having splitted eigenstate which it is not the ground or excited state, but rather the dressedstate, is tied to the concept of rabi splitting, which is literraly the energy gap of this two eigenstate.
En=En,+−En,−=ℏΩ