Two Level Atom With photon Algebra

Contents2 sections
  1. The combined operator
  2. Commutation

The combined operator§

There are four combination worth mentioning on, the rest is trivial / mentioned previously. Which is

a^σ^+a^σ^+a^σ^a^σ^\hat{a}\hat{\sigma}^+ \quad \hat{a}^\dagger\hat{\sigma}^+ \quad \hat{a}\hat{\sigma}^- \quad \hat{a}^\dagger\hat{\sigma}^-

Since photon operators and atom operators commute, the combination can be seen as a single operator as whole.

Commutation§

[a^σ^+,a^σ^+]=1(σ+)2=0[\hat{a}\hat{\sigma}^+,\hat{a}^\dagger\hat{\sigma}^+]=1(\sigma^+)^2=0 [a^σ^+,a^σ^]=(a^)2(σ^eσ^g)[\hat{a}\hat{\sigma}^+, \hat{a}\hat{\sigma}^-]=(\hat{a})^2(\hat{\sigma}_e-\hat{\sigma}_g) [a^σ^+,a^σ^]=a^a^(σ^eσ^g)+σ^σ^+=(n^+1)σ^en^σ^g[\hat{a}\hat{\sigma}^+,\hat{a}^\dagger\hat{\sigma}^-]= \hat{a}\hat{a}^\dagger(\hat{\sigma}_e-\hat{\sigma}_g)+ \hat{\sigma}^-\hat{\sigma}^+=(\hat{n}+1)\hat{\sigma}_e-\hat{n}\hat{\sigma}_g [a^σ^+,a^σ^]=n^(σ^eσ^g)σ^g=n^σ^e(n^+1)σ^g[\hat{a}^\dagger\hat{\sigma}^+,\hat{a}\hat{\sigma}^-]=\hat{n}(\hat{\sigma}_e-\hat{\sigma}_g)-\hat{\sigma}_g=\hat{n}\hat{\sigma}_e-(\hat{n}+1)\hat{\sigma}_g [a^σ^+,a^σ^]=(a^)2(σ^eσ^g)[\hat{a}^\dagger\hat{\sigma}^+,\hat{a}^\dagger\hat{\sigma}^-]=(\hat{a}^\dagger)^2(\hat{\sigma}_e-\hat{\sigma}_g) [a^σ^,a^σ^]=0[\hat{a}\hat{\sigma}^-, \hat{a}^\dagger\hat{\sigma}^-]=0

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